Where D represents a digit from 0 – 9, how many different ISBN numbers are possible if repetition of digits is allowed?
asked Jan 27, 2013 in Statistics Answers by anonymous

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1 Answer

This is something of an unfair question because the ISBN is currently 13 digits, but the last digit is a checksum digit calculated from all the others. So only 12 digits are independent, and since these 12 can each be any number from 0 to 9, there are 10^12 possible numbers: 1,000,000,000,000 from 000-0-000-00000-0 to 999-9-999-99999-4.

answered Nov 12, 2014 by Rod Top Rated User (487,420 points)
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