Let x=1 be the factor from single root and (x+1)2 be the factor associated with the double root, and let x=i and x=-i be the imaginary roots, so the polynomial looks like (x-1)(x+1)2(x-i)(x-i).
(x-i)(x-i)=x2+1; (x+1)2=x2-2x+1.
(x2+1)(x+1)2=x4-2x3+2x2-2x+1.
(x-1)(x+1)2(x-i)(x-i)=x5-2x4+2x3-2x2+x-x4+2x3-2x2+2x-1=
x5-3x4+4x3-4x2+3x-1. Graph is shown below.