Remember i^2 =-1
i^3 = -i
i^4 = 1
Given
W = 2+3i, Z = -3-2i
So, (2iW-4Z)/(2iZ-W)
=> {2i(2+3i) - 4(-3-2i)}/{2i(-3-2i) - (2+3i)}
=> (4i -6 +12 +8i)/(-6i +4 -2 -3i)
=> (6 + 12i)/(2-9i)
Multiply both numerator and denominator by conjugate of (2-9i)
=> {(6 + 12i)(2+9i)}/{(2-9i)(2+9i)}
=>(-96+78i)/85
=> -96/85 + i* 78/85