Using Gauss-Seidel method, evaluate the derived system of linear equation

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The Gauss-Seidel method diverges if we start the process with initial values of zero. No other starting point has been provided. Start by letting all variables=0. We use these and the equations below to derive subsequent iterations of the variables.


I₁=(7I₃-3I₂)/5, (I₁)₁=0 from initial conditions and from this equation.

I₂=(8+3I₁+2I₃)/5, (I₂)₁=8/5=1.6.

I₃=(5I₂+7I₁-16)/3, (I₃)₁=(8-16)/3=-8/3.

If we continue substituting for each iteration, the values diverge rapidly. Clearly, (0,0,0) is not a good starting point.

The linear equations lead to I₁=1, I₂=3, I₃=2 using other methods.

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