Can someone please help me with this.
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1 Answer

eˣ+y²=2,

eˣ+2yy'=0,

2yy'=-eˣ.

At (0,1): 2y'=-1, y'=-½, so the tangent line has a slope -½, and the normal has a slope -1/(-½)=2.

Use slope/intercept to get the tangent line and normal line equations:

TANGENT: y-1=-x/2, y=-x/2+1

NORMAL: y-1=2x, y=2x+1

Curve is in red; the tangent line is blue and the normal line is green.

by Top Rated User (762k points)

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