Legend tells of a Roman general who was so successful in his campaigns that the emperor offered
the general his choice of reward. The general asked the emperor for all the silver that he could carry
out of the imperial treasury in one month (31 days). The emperor agreed, but offered two
conditions.
On the first day, the general would receive 1 silver denarius. On the second day, he would turn in the
previous day’s coin and receive a coin valued at 2 denarii. Each day, the general was to come to the
treasury turn in the previous day’s coin and the treasurer would mint a special coin that would be
twice as heavy and worth twice as much as the coin the general got a day earlier. One denarius coin
weighed about 0.006 kg. The largest object the general could carry or roll without help could weigh
no more than 300 kg.
Activity 1:
1. a. What function V(x) gives the value of the coin that the general received on day x? (2 pts)

b. What is the domain of this function? (1 pt)

2. Write a function M(x) that gives the mass of each coin in kilograms as a function of day x. (2
pts)

3. a. Use M(x) from Question 2 to write an inequality that describes the mass of a coin that the
general could carry or roll out of the treasury. (2 pts)

b. Make a table of values of this function. (3 pts)

c. Use the table to solve the inequality. (2 pts)

4. What is the total value of the coins that the general would receive?
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1 Answer

1. a. What function V(x) gives the value of the coin that the general received on day x? (2 pts)

V(x)=2ˣ⁻¹ denarii

 

b. What is the domain of this function? (1 pt)

Integer x>0

 

2. Write a function M(x) that gives the mass of each coin in kilograms as a function of day x. (2

pts)

M(x)=0.006(2ˣ⁻¹) kg

 

3. a. Use M(x) from Question 2 to write an inequality that describes the mass of a coin that the

general could carry or roll out of the treasury. (2 pts)

M(x)≤300, 0.006(2ˣ⁻¹)≤300, 2ˣ⁻¹≤300/0.006=300000/6=50000, 2ˣ⁻¹≤50000, x-1≤log₂50000. Since 2¹⁶=65536, x-1<15, M(16)≤0.006×32768=196.608kg.

b. Make a table of values of this function. (3 pts)

x        2ˣ⁻¹       M (kg)

1           1         0.006

2           2        0.012

3          4         0.024

4          8         0.048

5        16          0.096

6        32          0.192

7        64          0.384

8      128          0.768

9      256          1.536

10     512          3.072

11    1024          6.144

12   2048        12.288

13   4096       24.576

14    8192       49.152

15  16384        98.304

16  32768      196.608

17   65536     393.216

 

c. Use the table to solve the inequality. (2 pts)

M≤196.608

4. What is the total value of the coins that the general would receive?

32768 denarii

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