the height h(t) in feet of an object thrown into the air with an initial upward velocity of 63 feet per second is given by the formula h(t)=-16t^2+63t+20 where t is the time in seconds. What's the height of the object after 2 seconds?
by
reopened

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

Best answer

Question 1.

f(t)=-5t²+20t+5=5(-t²+4t+1)=

5(-t²+4t-4+4+1)=

5(5-(t-2)²). This is maximum when t=2, and the maximum height is therefore 5×5=25m.

Question 2.

h(2)=-64+126+20=82ft.

by Top Rated User (884k points)

Related questions

Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
86,811 questions
93,393 answers
2,336 comments
24,169 users