the height h(t) in feet of an object thrown into the air with an initial upward velocity of 63 feet per second is given by the formula h(t)=-16t^2+63t+20 where t is the time in seconds. What's the height of the object after 2 seconds?

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1 Answer

Best answer

Question 1.



5(5-(t-2)²). This is maximum when t=2, and the maximum height is therefore 5×5=25m.

Question 2.


by Top Rated User (884k points)

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