Please help ASAP. Thanks!

asked Jul 25 in Calculus Answers by 1998cm Level 1 User (940 points)

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

Best answer

x²+x-6=(x+3)(x-2), so (x²+x-6)/(x-2)=x+3 for all values of x except x=2. So there is a discontinuity at x=2 only. Note that when x=-3, we get 0/(-5)=0 making the function continuous at x=-3. The discontinuity at x=2 is because we get 0/0 which cannot be evaluated, but it is just a singularity (hole) that does not occur for any other value of x.

answered Jul 25 by Rod Top Rated User (582,800 points)
selected Jul 25 by 1998cm

Related questions

Welcome to, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
81,657 questions
85,896 answers
69,324 users