I’m not sure on how to get from this...

x^2(b-c)+b^2(c+x)-c^2(x+b)

to this...

(b-c)(x+b)(x+c)

without having to expand everything first and rather putting the equation into an ax^2+ bx + c format
in Algebra 1 Answers by

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1 Answer

Best answer

Expand some brackets:

x²(b-c)+b²c+b²x-c²x-bc².

Regroup: x²(b-c)+x(b²-c²)+bc(b-c)=x²(b-c)+x(b-c)(b+c)+bc(b-c).

Common factor is b-c:

(b-c)(x²+(b+c)x+bc)=(b-c)(x+b)(x+c)

 

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