The ratio of small to large was 1 to 6
asked Dec 5 in Algebra 1 Answers by anonymous

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let L is the number of large and S is the number of small, thren we have: L - 3S = 30 (1) and S/L=1/6 (2)

solving the (1) for L we get L = 30 + 3S substituting this value of L to (2) we get S/(30+3s) = 1/6

and 30+3S = 6S  --->>>  30 = 3S  And S = 10 sustituting this value os S to (1) we get L=60
answered Dec 6 by tadinn Level 4 User (6,320 points)
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