In 7th acc math
in Algebra 1 Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

There are 14-x quarters worth 25(14-x) cents, the dimes are worth 10x cents.

25(14-x)+10x>220.

350-25x+10x>220, 130>15x, so x<130/15, x<26/3, x≤8, and or -8≤-x and 14-8≤14-x, 6≤14-x.

Therefore he needs 6 or more quarters (and 8 or fewer dimes).

by Top Rated User (906k points)

Related questions

Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
86,901 questions
93,939 answers
2,339 comments
24,250 users