Find two consecutive even integers such as that the smaller added to two times the larger gives a sum of 34.
even integers are multiples of 2.
Let the two consecutive even integers be n1 and n2. Then ...
n1 = 2n, n = 1,2,3,...
n2 = 2(n+1), n = 1,2,3,...
n1 + 2*n2 = 34 (the smaller added to two times the larger gives a sum of 34)
2n + 2*{2(n+1)} = 34
2n + 4n + 4 = 34
6n = 30
n = 5
The two numbers are: m1 = 10 and m2 = 12