Can anyone tell me the answer to this/how to work it would help me a lot.
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Let the numbers be a and b. So a-b=15 where a is the larger number.

8 added to twice the greater number is 2a+8; 4 less than 3 times the lesser number is 3b-4.

These two quantities are equal so 2a+8=3b-4; rearranging this we get 3b-2a=12.

So now we have a system of two equations involving two variables a and b.

We can write b=a-15 and then substitute for b in the other equation:

3(a-15)-2a=12; 3a-45-2a=12, a=12+45=57, so b=57-15=42.

Let's see if this is right.

2a+8=122; 3b-4=122, so the numbers are 57 and 42.

by Top Rated User (796k points)

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