y=x^2 -4x -32. Use this function and identify the axis of symmetry and the vertex. Thank you.


asked Jan 10 in Algebra 1 Answers by swizzy500 (120 points)

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:

To avoid this verification in future, please log in or register.

2 Answers

y=x^2-4x+4-36 is another way of expressing this (by completing the square). This is the same as y=(x-2)^2-36. When y=0 x-2=±6 which identifies the x intercepts as x=2+6=8 and x=2-6=-4. The axis of symmetry lies midway between these two points, when x=2, which is the equation of the axis of symmetry. As you can see, it's equidistant (6 units) from the x intercepts. The vertex is on this line, and y=-36 when x=2, so the vertex is at (2,-36).

answered Jan 10 by Rod Top Rated User (487,100 points)
answered Jan 10 by Mathical Level 10 User (57,460 points)
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
79,823 questions
83,639 answers
66,565 users