I really hope If you can solve this for me
asked Oct 30, 2016 in Trigonometry Answers by cautionc

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1 Answer


Put A in place of ?.

Multiply top and bottom by sinA-icosA:



Numerator: 1-cos^2(A)+isinA(1+cosA+1-cosA)-sin^2(A)=


Denominator: 1-2cosA+cos^2(A)+sin^2(A)=2-2cosA.


But sinA=2sin(A/2)cos(A/2) and cosA=1-2sin^2(A/2),

so isinA/(1-cosA)=2isin(A/2)cos(A/2)/2sin^2(A/2)=icot(A/2).

Therefore, (1+a)/(1-a)=icot(A/2) QED


v has been assumed to represent square root.






So x^2-y^2=(ac+bd)/(c^2+d^2) and 2xy=(bc-ad)/(c^2+d^2).

Also, 1/(x+iy)=(x-iy)/(x^2+y^2)=




More to follow...

answered Nov 1, 2016 by Rod Top Rated User (487,100 points)
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