Divisibility by 11 is tested by taking the difference of the sums of alternate digits: A+C+A-2B=11n, where n is an integer. Put A=9 and B=8: 2A+C-2B=18+C-16=11n. C+2=11n. If n=1, C=9. The number is therefore 98,989. But C has to be distinct. Reduce B to 7: 18+C-14=11; C=11-4=7=B, so again C is not distinct. But a pattern is emerging. Reduce B to 6: 18+C-12=11 and C=5, which is distinct, and the number is 96,569.