Problem: melanie left the city for vacation. mike left 3 hours later going 60 mph faster to catch up. after 2 hours mije caught up. what was melanie's average speed?
Distance, rate
d = s * t
d = s * 5hrs <<< Melanie
d = (s + 60) * 2hrs <<< Mike
Both traveled the same distance.
s * 5 = (s + 60) * 2
5s = 2s + 120
3s = 120
s = 40 <<< Melanie's speed
s + 60 = ??
40 + 60 = 100 <<< Mike's speed
40 * 5 = 200
(40 + 60) * 2 = 100 * 2 = 200
Answer: Melanie's average speed was 40 mph.
I don't think that having Mike travel
at 100 mph is a good idea.