I need it for home work and i need help please its hard
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2 Answers

J=Justin's money; A=Ava's; E=Emma's.

J=A+7.5; E=J-12; A+E+J=63. So A=J-7.5. Now we have E and A in terms of J.

Substitute for A and E: J-7.5+J-12+J=63; 3J-19.5=63, 3J=63+19.5=82.5, so J=82.5/3=27.5 or $27.50.

So A=27.5-7.5=$20; E=27.5-12=$15.50.

CHECK: Justin has $7.50 more than Ava. True. Emma has $12 less than Justin. True. Together they have $63. True.
by Top Rated User (884k points)
Let's keep it a problem with one variable

Since Justin has 7.50$ more than Eva, and Emma has 12$ less than justin then we will have:

Eva has X dollars, and justin must have X+7.50$ then Emma should have X+7.50$ -12$ =X - 4.50$

The total is 63$ therefore  (Eva's  X  + Justin's  X + 7.50$  + Emma's X - 4.50$) = 63

X + X + 7.50 + X - 4.50 = 63 therefore 3X + 3 = 63 let's divide everything by three to simplify 3X/3 + 3/3 = 63/3

X + 1 = 21  therefore  X = 21 - 1 = 20  Eva has 20$,  Justin has 20$ + 7.50$= 27.50$ and Emma has 27.50$ - 12$ = 15.50$
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