answer must be given correct to 1 decimal place.There is no perimeter given.
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2 Answers

Let a the length, And b the width, Then: a=b+3 b=a-3 A=a*b=a(a-3)=a²-3a (cm²) But a²-3a=30 (cm²) a²-3a-30=0 D=(-3)² -4*(-30)=129, a=½[3±|√129] a=½[3+√129]
by Level 12 User (101k points)

let

    length="l"

    width="w"

if..length=l,then w=l+3  (from the relation given)

Area=l*(l+3)

30=l^2+3l

l^2+3l-30=0

from the general quadratic formula

l=[-3+(3^2+120)^1/2]/2

l=[-3+(129)^1/2]/2

l=4.175cm

 

 

 

 

 

 

 

 

 

 

 

 

by Level 3 User (4k points)

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