Here lies the remains of diophantus.he was a child for one sixth of his life.after one twelfth more,he became a man.after one seventh more,he married,and five years later his son was born.his son lived half as long as his father and died four years before his old was diophantus when he died???
asked Mar 15, 2014 in Algebra 1 Answers by anonymous

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

Let x be the age to find out.


X = childhood + adulthood + time to marriage + 5 yrs (sons birth) + son' age + 4 years

X.  =.  X/6.      + x/12.        + x/7.      + 5.   +x/2.      + 4.

0 = x/6 + x/12 +x/7 _ x/2 + 9         (transposing x from LHS)

0 = 14x + 7x + 12x _ 42x + 84* 9.      (multiply by 84    Common denominator)

9x = 84*9.    (transpose x terms to,left)

So the age is. 84
answered Mar 16, 2014 by anonymous

Related questions

2 answers
Welcome to, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
81,617 questions
85,852 answers
69,284 users