the committee format will be MMMMM,WMMMM,WWMMM, WWWMM, WWWWM
method one: all the possible committee : 10C5
the committee with only Men : 6C5
thus the require committee will be 10C5 - 6C5 = 246
method two : committee with one Woman = 4C1 x 6C4 = 60
committee with two Women = 4C2 x 6C3 =120
committee with three Women = 4C3 x 6C2 = 60
committee with four Women = 4C4 x 6C1= 6
total number of committees = 60+120+60 + 6 = 246