what is the sum of number

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2 Answers

2352=24*98,so the 2 numbers=24 & 98

24+98=122
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product of HCF and LCM = 2352*98 = 230496

factor of 230496 = 2^5 * 3 * 7^4 .

now by hit and trial try to find two numbers using above factors ----:::

first number = 2^2 * 7^2 = 196 .

second number = remaining of other factors = 2^3 * 3 * 7^2 = 1176 .

and now the sum of two numbers is 1176 + 196 = 1372 .
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