Find a number such that one-half of the number is 7 less than 2/3rds of the number.
Let the numer = x
one-half of the number = x/2
2/3rds of the number = 2x/3
one- half of the number = 2/3rds of the number -7 { Given }
x/2 =(2x/3) -7
x/2 = (2x -7 *3 )3 {LCM = 3}
3x = 2(2x -21) { doing cross multiplication }
3x = 4x - 42
3x - 4x = -42
-x = -42
x = 42