2z=8 , 3y-z=-1 ,2x+y+z=11 solve the linear system by substitution
2z=8 , 3y-z=-1 ,2x+y+z=11 solve the linear system by substitution
2z = 8
3y - z = -1
2x + y + z = 11
2z = 8
z = 4
3y - z = -1
3y - 4 = -1
3y = 3
y = 1
2x + y + z = 11
2x + 1 + 4 = 11
2x + 5 = 11
2x = 6
x = 3
Answer: x = 3, y = 1, z = 4