sqrt(x+3 - sqrt(x-4)=1
I'm assuming that,
1) you want to solve for x
2) that threre is a bracket missinng - the exprression shouild be
sqrt(x+3) - sqrt(x-4) =1 OK, now square both sides to give,
(x + 3) - 2.sqrt(x+3)*sqrt(x-4) + (x - 4) = 1 simplify this to,
2x - 2 = 2.sqrt(x+3)*sqrt(x-4) square both sides again.
4x^2 - 8x + 4 = 4(x+3)(x-4) multiply out the brackets
4x^2 - 8x + 4 = 4x^2 - 4x - 48
0 = 4x - 52
4x = 52
x = 13