Forty eight decreased by a # is the same as the dif. of four times th num and 7
this is what i have idk if its right. 48-x=4*x+7
The statement "the dif. of four times th num and 7" refers to subtraction. It means the
difference between two numbers: 4x is one number, and 7 is the other number.
48 - x = 4x - 7
48 + 7 = 4x + 4
5x = 55
x = 11 <<<<<<<<<
Check it.
48 - 11 = 4(11) - 7
37 = 44 - 7
37 = 37
Solving the equation you suggested doesn't produce an integer for x.
48 - x = 4x + 7
5x = 41
x = 8 1/5
Solving your equation gives 39.8 = 39.8